PHAR 7632 Spring 1999

Biopharmaceutics

OU HSC College of Pharmacy

Final Exam 5 May 1999 - Answers - Section 3 Q4

Q 3.4 (10 points) A drug is known to follow one compartment pharmacokinetics. The elimination rate constant in patients with normal renal function is approximately 0.39 hr-1, the apparent volume of distribution is 35.7L, and the value of fe is 0.35. Assume that metabolism is unaffected by changes in renal function. Calculate the expected elimination half-life in patients with only 30% of normal renal function.

kel = 0.39 hr-1 (t1/2 = 1.78 hr)

fe = 0.35

ke = 0.1365 hr-1

km = 0.39 - 0.1365 = 0.2535 hr-1

ke(patient) = ke x 0.3 = 0.04095 hr-1

km(patient) = 0.2535 hr-1

kel(patient) = 0.04095 + 0.2535 = 0.294 hr-1

t1/2 (patient) = 2.36 hr