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Continuous IV Infusion - Steady State

The Model

Giving the drug by infusion will alter the kinetics of the drug.

Schematically:

IV Infusion - One Compartment Scheme
Figure 15.2.1 Scheme for One Compartment Intravenous Infusion

In Figure 15.2.1 we have added an infusion rate constant, k0, to the diagram presented earlier, (Figure 5.4.1). This is a zero order process so the units of k0 are be amount per time, for example 25 mg/min.

Differential and Integrated equation

The differential equation for V*Cp is then:

dX/dt

Equation 15.2.1 Differential Equation for Drug amount During an IV Infusion

Equation 15.2.1 is the differential equation during the infusion period and it can be integrated to give Equation 15.2.2 using Laplace transforms.

X versus time

Equation 15.2.2 Integrated Equation for Drug Amount in the body versus Time

and after dividing both sides by the apparent volume of distribution, V.

Cp versus time

Equation 15.2.3 Integrated Equation for Drug Concentration versus Time


Javascript Calculators using Equation 15.2.3

Calculate Cp Given k0, kel and V at time t

Enter your own values into each field
k0 (zero order mass/time)
kel (first order reciprocal time)
V (volume)
t (time)
 
Cp (mass/volume) is:
Calculate k0 required to give Cp at time t

Enter your own values into each field
Desired Cp (mass/volume)
kel (first order reciprocal time)
V (volume)
t (time)
 
k0 (mass/time) is:

You may notice that Equation 15.2.3 for Cp is quite similar to Equation 12.3.4 we had before for the cumulative amount of drug excreted into urine. As you might expect the plot of Cp would be similar in shape.

Cp versus time

Figure 15.2.2 Linear Plot of Cp versus Time During a Continuous Infusion

Click on the figure to view the Java Applet window
Java Applet as a Semi-log Plot


If we continue the infusion indefinitely then we will approach a steady state plasma concentration when the rate of infusion will be equal to the rate of elimination.

This is because the rate of infusion will be constant whereas the rate of elimination will increase as the plasma concentration increases. At steady state the two rates become equal. We can determine the steady state concentration from the differential equation by setting the rate of change of Cp, i.e. dCp/dt = 0.

Then

dX/dt

therefore

Equation 15.2.4 Steady State Concentration after Continuous IV Infusion

This could also be calculated from the integrated equation by setting e- kel * t = 0 at t = ∞.

We can now calculate the infusion rate necessary to produce some desired steady state plasma level.

For Example:

A desired steady state plasma level of theophylline maybe 15 mg/L. The average half-life of theophylline is about 4 hr and the apparent volume of distribution is about 25 liter. What infusion rate is necessary?

First, kel = 0.693/4 = 0.17 hr-1

then k0 = kel * V * Cp = 0.17 * 25 * 15 = 63.8 mg/hr

We would probably use an infusion of 60 mg/hr which would produce a Cpss value given:

Cpss = k0/(kel • V) = 60/(0.17 x 25) = 14.1 mg/L


Javascript Calculators using Equation VI-3

Calculate Cpss Given k0, kel and V

Enter your own values into each field
k0 (zero order mass/time)
kel (first order reciprocal time)
V (volume)
 
Cpss (mass/volume) is:
Calculate k0 required to give Cpss

Enter your own values into each field
Desired Cpss (mass/volume)
kel (first order reciprocal time)
V (volume)
 
k0 (mass/time) is:

For practice try calculating concentrations or required infusion rates. Compare your answers with the computer! These problems includes calculation of drug concentration or required infusion rates during an IV infusion or at steady state.

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Copyright 2001-3 David W. A. Bourne (david@boomer.org)