t(Cp = 10 mg/L) and New Dose

Dose = 1000 mg
Cp(2 hr) = 18.6 mg/L
Cp(12 hr) = 13.1 mg/L)

kel = (ln(18.6) - ln(13.1))/(12 - 2) = 0.0351 hr^-1

Cp(0) = Cp(2 hr)/e^{-kel • 2} = 18.6/e^{-0.0351 • 2} = 20 mg/L

Next dose to be given at t(≈ 10 mg/L) = -ln(10/20)/kel = 19.7 => 20 hr

From Cp⁰ = 20 mg/L the V = Dose/Cp⁰ = 1000/20 = 50 L

The next dose needs to jump the concentration from 10 to 25 mg/L, and increase of 15 mg/L. The next dose is ΔCp • V = 15 x 50 = 750 mg.

Figure 4.12.1

Linear Plot of Cp versus Time after IV Bolus Administration One Compartment Model

Try simulating concentration versus time after an IV bolus according to a one compartment model. Add additional lines with different parameter values using the Add Line button.