Timehr |
Cpmg/L |
ΔAUCmg.hr/L |
AUCmg.hr/L |
Cp • tmg.hr/L |
ΔAUMCmg.hr ^{2}/L |
AUMCmg.hr ^{2}/L |

0 | 2.81 | 0 | 0 | 0 | 0 | 0 |

0.25 | 2.43 | 0.655 | 0.655 | 0.608 | 0.0759 | 0.0759 |

0.5 | 2.18 | 0.576 | 1.23 | 1.09 | 0.212 | 0.288 |

0.75 | 2.02 | 0.525 | 1.76 | 1.52 | 0.326 | 0.614 |

1 | 1.9 | A | C | 1.9 | 0.427 | 1.04 |

1.25 | 1.82 | B | 2.71 | 2.28 | 0.522 | 1.56 |

1.5 | 1.75 | 0.446 | 3.16 | 2.63 | D | F |

2 | 1.65 | 0.85 | 4.01 | 3.3 | E | 3.66 |

4 | 1.36 | 3.01 | 7.02 | 5.44 | 8.74 | 12.4 |

6 | 1.13 | 2.49 | 9.51 | 6.78 | 12.2 | 24.6 |

9 | 0.857 | 2.98 | 12.5 | 7.71 | 21.7 | 46.4 |

12 | 0.65 | 2.26 | 14.7 | 7.8 | 23.3 | 69.6 |

24 | 0.215 | 5.19 | 19.9 | 5.16 | 77.8 | 147 |

Infinity | 0 | G | H | 0 | I | J |

will prevent you getting credit for this problem

You will have one chance to submit your answers for this problem [# 3520138200]. You can try the homework problem more than once with different data to improve your grade. Your highest score is recorded. After submitting your answers you can use the browser back arrow to get back here and see how the compuer worked the problem.

**Equation 30.4.1 AUC for the segment from i-1 to i**

**Equation 30.4.2 AUC for the last segment from t _{last} to infinity**

where k' is the slowest rate constant. k' can be calculated from the terminal slope of Cp versus time on semi-log graph paper.

**Equation 30.4.3 AUMC for the last segment from t _{last} to infinity**

where k' is the slowest rate constant. k' can be calculated from the terminal slope of **Cp versus time** on semi-log graph paper.

**Equation 30.4.4 Mean Resident Time (MRT)**

**Equation 30.4.5 Clearance (CL)**

**Equation 30.4.6 Steady State Apparent Volume of Distribution, V _{ss}**

Last update: Thu 19 Jan 2012 09:10:00 am