1) Since Cp(ss) = k0/(kel*V); k0 can be calculated as Cp(ss) * kel * V = 25 x 0.099 x 25 = 61.9 mg/hr
2) To achieve Cp(0) = 25 mg/L with a bolus dose give Cp(0) * V = 25 x 25 = 625 mg
3) To reach Cp(0.5) = 25 mg/L with a fast infusion rearrange: Cp(T) = (k0/(kel*V)) * (1 - e-kel*T) to give k0(fast) = Cp(T)*kel*V/(1-e-kel*T) = 25 x 0.099 x 25/(1 - e-0.099 x 0.5) = 1280 mg/hr for 30 minutes (ONLY!!!)
Sketch as a linear graph
1) Slow infusion - blue squares
2) I.V. Bolus - green circles
3) Fast infusion - red triangles
Parameter | Value | Units |
k0(slow) | 61.9 | mg/hr |
Dose (bolus) | 625 | mg |
k0(fast) | 1280 | mg/hr |