+ 
= kel + k12 + k21 = 2.84
hr-1
* = kel * k21 = 0.21
hr-1
= 2.76 hr-1
=0.076 hr-1
-k21)/(V *
(- )) = 7.734 hr-1
)/(V * (- )) = 8.713 hr-1
*t + B * e-*t
Question 1.
Given kel = 0.14 hr-1, k12 = 1.2 hr-1, k21 = 1.5 hr-1, V = 15.2 L, and Dose = 250 mg.
Calculate
+ = kel + k12 + k21 = 2.84
hr-1
* = kel * k21 = 0.21
hr-1
= 2.76 hr-1
=0.076 hr-1
-k21)/(V *
(- )) = 7.734 hr-1
)/(V * (- )) = 8.713 hr-1
*t + B * e-*t
Results
|
Time (hr) |
Cp (mg/L) |
|
0 |
16.45 |
|
0.25 |
12.42 |
|
0.5 |
10.33 |
|
1 |
8.56 |
|
2 |
7.52 |
|
4 |
6.43 |
|
6 |
5.52 |
|
8 |
4.74 |
|
10 |
4.08 |
|
12 |
3.50 |
Linear Plot
Semi-log Plot
