Time (hr) |
Cp (mg/L) |
0.125 |
14.00 |
0.25 |
11.50 |
0.5 |
8.42 |
0.75 |
6.81 |
1 |
5.95 |
1.5 |
5.19 |
2 |
4.88 |
3 |
4.53 |
4 |
4.23 |
6 |
3.71 |
9 |
3.05 |
12 |
2.50 |
18 |
1.68 |
24 |
1.13 |
The green line and symbols represent the
Cplate
line. A value for can be calculated
from this line to be
0.0662 hr-1 with the intercept value, B = 5.53 mg/L.
The table below can be completed with the calculation of the residual
(= Cp - Cplate). Plotting the
Residual versus time gives the
red line on the graph above. From this line it is possible to
calculate
= 2.74 hr-1
(from the slope) and A = 12.0 mg/L (from the intercept)
Time (hr) |
Cp (mg/L) |
Cplate (mg/L) |
Time (hr) |
Residual (mg/L) |
0.125 |
14 |
5.49 |
0.125 |
8.51 |
0.25 |
11.5 |
5.44 |
0.25 |
6.06 |
0.5 |
8.42 |
5.35 |
0.5 |
3.07 |
0.75 |
6.81 |
5.27 |
0.75 |
1.54 |
1 |
5.95 |
5.18 |
1 |
0.77 |
1.5 |
5.19 |
5.01 |
|
|
2 |
4.88 |
4.85 |
|
|
3 |
4.53 |
4.54 |
|
|
4 |
4.23 |
|
|
|
6 |
3.71 |
|
|
|
9 |
3.05 |
|
|
|
12 |
2.5 |
|
|
|
18 |
1.68 |
|
|
|
24 |
1.13 |
|
|
|
Parameter | Value | Units |
![]() | 2.74 | hr-1 |
![]() | 0.0662 | hr-1 |
A | 12.0 | mg/L |
B | 5.53 | mg/L |
= 0.910 hr-1
= 0.200 hr-1
= 1.70 hr-1
= 17.1 L
= 51.5 L