| Time (hr) | Cp (mg/L) | Δ (AUC mg.hr/L) | AUC (mg.hr/L) |
|
0 |
|||
|
0.5 |
3.61 | ||
|
1 |
2.6 | ||
|
2 |
1.77 | ||
|
4 |
0.7 | ||
|
6 |
0.29 | ||
|
8 |
0.13 | ||
|
10 |
0.05 | ||
|
∞ |
The table above provides a set of data for you to analyze. Use these data with the trapezoidal rule shown in the equations below to calculate each AUC segment including the last segment. The first segment is calculated using the concentration at time zero calculated by (back) extrapolation from the data provided. The data should be plotted on semi-log graph paper and a best-fit line drawn through the data. The point where this line crosses the y-axis is the y intercept or your estimate of Cp(0). Use a point on the other end of the line and calculate kel with the equation below. Estimate the area from zero to the last data point using the trapezoidal rule. Add the area for the last segment to get the total area under the curve.
You will have one chance to submit your answers for this problem [# 1360646469]. You can try the homework problem more than once with different data to improve your grade. Your highest score is recorded. After submitting your answers you can use the browser back arrow to get back here and see how the compuer worked the problem.
Don't forget the first and last segments. You will need to extrapolate the concentration back to the intercept for the first segment. You will also need kel to calculate the last segment:
Calculate kel from points on the best-fit line.
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