Returning to the equation for Cp as a function of time
Equation IX-1 from earlier
we can calculate ka and kel given Cp versus time data. From the method of residuals, the intercept can be determined as
Since we know the DOSE and have calculated ka and kel, it is possible to calculate . However, with only data from a single administration available that's all we can determine, we cannot separate V and F. Of course if we have IV data for kel and V, we could use this to determine F.
Thus F must be determined by comparison with another dose administration. If the other dosage form is an intravenous form then the F value is termed the absolute bioavailability. In the case where the reference dosage form is another oral product, the value for F is termed the relative bioavailability.
When a bioavailability study is conducted at least two dosage forms are administered to each subject. One dosage form is the product to be tested, while the other dosage form is a standard or reference dosage form. This may be an IV dose, oral solution or most commonly the original manufacturer's product. The doses are given with sufficient time between administrations for the drug to "washout" or be completely eliminated. We usually assume that each subject eliminates each dosage form at the same rate.
During the derivation of the Wagner-Nelson equations we calculated Amax, the maximum amount absorbed as:-
Amax = V * kel *
= V * kel * AUC
= F * DOSE
therefore
F =
Now by giving two dosage forms A and B, and calculating AUC values for each.
and if DOSEA = DOSEB and if we can assume that kelA = kelB and VA = VB then:-
Thus a relative bioavailability, F, can be calculated. If the B dosage form is given IV then FB = 1 and F = FA and thus FA can be called the absolute bioavailability.
EXAMPLE:
AUCA = 12.4 mg.hr/L [Dose = 250 mg] and AUCB = 14.1 mg.hr/L [Dose = 200 mg
We can do the same thing using urine data alone.
Since
fe =
Equation IX-2 Fraction Excreted Unchanged
therefore
F =
and for two dosage forms
again if DOSEA = DOSEB and feA = feB then
F =
EXAMPLE:
250 mg dose; UA = 175 mg; UB = 183 mg; F = = 0.96