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Multi Compartment Pharmacokinetic Models

The Laplace transform method can be extended to multi compartment pharmacokinetic models. The algebra gets more involved or maybe you can use the convolution technique. Using the algebraic approach we can develope the differential equations and thus the integrated equation for the two compartment model [Mayersohn, M. and Gibaldi, M 1971 "Mathematical Methods in Pharmacokinetics. II. "Solution of the Two Compartment Open Model," Amer. J. Pharm. Ed., 35:19-28].

Two compartment Model

Figure 7.5.1 A Two Compartment Pharmacokinetic Model

Following an IV bolus dose the drug is placed in component 1. Drug concentration in this component achieves equilibrium quickly. More slowly the drug either distributes into and out of various tissues and body fluids designated component 2 or is eliminated from the body as described by the first order rate constant, kel. The distribution processes are usually described using first order rate constants. Alternately, the elimination and distribution could be describe by clearance terms. For the purposes of this derivation we will confine the mathematical model to use rate constants. The differential equations for both components are shown below:

Differential equations for a two compartment model

Equations 7.5.1 Differential Equations for the Two Compartment Model after an IV Bolus Dose

Using the rules from Chapter 2 it is possible to write the Laplace transform of each of the equations.

Laplace transforms of the Equation 7.5.1

Equations 7.5.2 Laplace Transforms for the Equations 7.5.1

Since the amount of drug in component 2 is zero at time 0 the term, X02 can be set to 0. Equation 7.5.2.b becomes:

Laplace of component X2

Equation 7.5.3 Laplace Transform of the Amount in Component 2

With X01 the Dose we can substitute the value in Equation 7.5.3 for the Laplace of the amount in component 2 into Equation 7.5.2.b to continue the derivation of the Laplace of component 1.

Derivation of Laplace of Component 1

Equation 7.5.4 Deriving the Laplace of the Amount in Component 1

And now the fun stuff. We can make a substitution to simplify Equation 7.5.4. Looking at:

Alpha and Beta introduced

Equation 7.5.5 Introducing the terms α and β

Looking at Equation 7.5.5 and the last term in Equation 7.5.4 we can make the substitutions:

α + β = k12 + kel + k21

and α x β = kel x k21

to derive the final equation for the Laplace of the amount in component 1.

Laplace of the Amount in Component 1

Equation 7.5.6 Laplace of the Amount in Component 1


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